(x+2)^(2)-5=7

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Solution for (x+2)^(2)-5=7 equation: 



(x+2)^(2)-5=7

We move all terms to the left:

(x+2)^(2)-5-(7)=0

We add all the numbers together, and all the variables

(x+2)^2-12=0

We move all terms containing x to the left, all other terms to the right

(x+2)^2=12

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